## Chapter 16 - Current & Electricity - 4

 1. Matching Items..... Ohm�s lawa) W=QV b) 1/Re = 1/R1 + 1/R2 + 1/R3c) Re = R1 + R2 + R3d) V= IR
 2. Matching Items..... Joule�s lawa) 1/Re = 1/R1 + 1/R2 + 1/R3 b) R= p x L / Ac) Re = R1 + R2 + R3d) W=QV
 3. Matching Items..... Series circuita) 1/Re = 1/R1 + 1/R2 + 1/R3 b) 1 x 106 Ohmc) Re = R1 + R2 + R3d) R= p x L / A
 4. Matching Items..... Parallel circuita) 1 x 103 Ohm b) 1 x 106 Ohmc) 1/Re = 1/R1 + 1/R2 + 1/R3d) R= p x L / A
 5. Matching Items..... Specific Resistancea) 1 x 10-3 Ohm b) 1 x 106 Ohmc) R= p x L / Ad) 1 x 103 Ohm
 6. Matching Items..... 1 mega Ohma) 1 x 106 Ohm b) 1 x 10-3 Ohmc) 1 x 10-6 Ohmd) 1 x 103 Ohm
 7. Matching Items..... 1 Kilo Ohma) 1 x 106 Ohm b) 1 x 103 Ohmc) 1 x 10-3Ohmd) 1 x 10-6 Ohm
 8. Matching Items..... 1 Milli Ohma) 1 x 10-6 Ohm b) 1 x 10-3 Ohmc) 1 x 10-4 Ohmd) 1 x 106 Ohm
 9. Matching Items..... 1 micro Ohma) 1 x 10-9 Ohm b) 1 x 10-6 Ohmc) 1 x 106 Ohmd) 1 x 103Ohm
 10. Matching Items..... 1 Nano Ohma) 1 x 10-3 Ohm b) 1 x 103 Ohmc) 1 x 10-6 Ohmd) 1 x 10-9 Ohm
 11. The rate of flow of electric charge through cross sectional area is _______.Click here to enter your answer!
 12. In SI system the unit of electric current is __________.Click here to enter your answer!
 13. The flow of electric current is due to motions of _______.Click here to enter your answer!